♨️ J/(kg·K) to BTU/(lb·°F) — Joule/(Kilogram·Kelvin) to BTU/(Pound·°F) Converter

Convert specific heat capacity units — J/(kg·K), BTU/(lb·°F), cal/(g·°C) and more.

1 unit =
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Formula 1 J/(kg·K) = 0.0002388459 BTU/(lb·°F)
All Joule/(Kilogram·Kelvin) conversions
UnitNameValue
kJ/(kg·K) Kilojoule/(Kilogram·Kelvin) 0.001
BTU/(lb·°F) BTU/(Pound·°F) 0.0002388459
cal/(g·°C) Calorie/(Gram·°C) 0.0002388459
kcal/(kg·°C) Kilocalorie/(Kilogram·°C) 0.0002388459
Related Specific Heat conversions
BTU/(lb·°F) → J/(kg·K) kJ/(kg·K) → BTU/(lb·°F)

How to convert Joule/(Kilogram·Kelvin) to BTU/(Pound·°F)

Multiply the number of Joule/(Kilogram·Kelvin)s by 0.000238846 to get BTU/(Pound·°F)s. Formula: BTU/(lb·°F) = J/(kg·K) × 0.000238846. Example: 10 J/(kg·K) × 0.000238846 = 0.00238846 BTU/(lb·°F). To reverse, divide BTU/(Pound·°F)s by 0.000238846 to get Joule/(Kilogram·Kelvin)s.

Worked examples

Example 1
1 J/(kg·K) × 0.000238846 = 0.000238846 BTU/(lb·°F)
1 Joule/(Kilogram·Kelvin) equals 0.000238846 BTU/(Pound·°F).
Example 2
5 J/(kg·K) × 0.000238846 = 0.00119423 BTU/(lb·°F)
5 Joule/(Kilogram·Kelvin) equals 0.00119423 BTU/(Pound·°F).
Example 3
10 J/(kg·K) × 0.000238846 = 0.00238846 BTU/(lb·°F)
10 Joule/(Kilogram·Kelvin) equals 0.00238846 BTU/(Pound·°F).
Example 4 — reverse
1 BTU/(lb·°F) = 4186.8 J/(kg·K)
To convert back from BTU/(Pound·°F) to Joule/(Kilogram·Kelvin), divide by 0.000238846 or use the swap button above.

Joule/(Kilogram·Kelvin) to BTU/(Pound·°F) — reference table

Joule/(Kilogram·Kelvin) (J/(kg·K))BTU/(Pound·°F) (BTU/(lb·°F))
0.001 J/(kg·K)2.38846e-07 BTU/(lb·°F)
0.01 J/(kg·K)2.38846e-06 BTU/(lb·°F)
0.1 J/(kg·K)2.38846e-05 BTU/(lb·°F)
0.5 J/(kg·K)0.000119423 BTU/(lb·°F)
1 J/(kg·K)0.000238846 BTU/(lb·°F)
2 J/(kg·K)0.000477692 BTU/(lb·°F)
5 J/(kg·K)0.00119423 BTU/(lb·°F)
10 J/(kg·K)0.00238846 BTU/(lb·°F)
20 J/(kg·K)0.00477692 BTU/(lb·°F)
50 J/(kg·K)0.0119423 BTU/(lb·°F)
100 J/(kg·K)0.0238846 BTU/(lb·°F)
250 J/(kg·K)0.0597115 BTU/(lb·°F)
500 J/(kg·K)0.119423 BTU/(lb·°F)
1000 J/(kg·K)0.238846 BTU/(lb·°F)
10000 J/(kg·K)2.38846 BTU/(lb·°F)

Quick conversion tips

1
Multiply by 0.000238846

To convert Joule/(Kilogram·Kelvin) to BTU/(Pound·°F), multiply by 0.000238846. Example: 10 J/(kg·K) = 0.00238846 BTU/(lb·°F)

2
Reverse: divide by 0.000238846

To convert BTU/(Pound·°F) back to Joule/(Kilogram·Kelvin), divide by 0.000238846 (multiply by 4186.8). Use the swap button above.

3
Round number check

Start with 100 Joule/(Kilogram·Kelvin)s = 0.0238846 BTU/(lb·°F) as your reference point. Scale up or down from there.

All Joule/(Kilogram·Kelvin) conversions

Reverse conversion

BTU/(lb·°F) → J/(kg·K)

Convert Joule/(Kilogram·Kelvin) to all other units

J/(kg·K) → kJ/(kg·K) J/(kg·K) → BTU/(lb·°F) J/(kg·K) → cal/(g·°C) J/(kg·K) → kcal/(kg·°C)

Related tools

All Specific Heat ConverterScientific Calculator

Frequently asked questions

1 Joule/(Kilogram·Kelvin) equals 0.000238846 BTU/(Pound·°F)s. Multiply any Joule/(Kilogram·Kelvin) value by 0.000238846 to get BTU/(Pound·°F)s.
10 Joule/(Kilogram·Kelvin)s equals 0.00238846 BTU/(Pound·°F)s. (10 × 0.000238846 = 0.00238846)
100 Joule/(Kilogram·Kelvin)s equals 0.0238846 BTU/(Pound·°F)s. (100 × 0.000238846 = 0.0238846)
Divide BTU/(Pound·°F) by 0.000238846 to get Joule/(Kilogram·Kelvin)s. Or multiply by 4186.8. Use the swap button on the converter above for instant reverse conversion.
Formula: BTU/(lb·°F) = J/(kg·K) × 0.000238846. Example: 5 J/(kg·K) × 0.000238846 = 0.00119423 BTU/(lb·°F).
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About Joule/(Kilogram·Kelvin) and BTU/(Pound·°F)

Joule/(Kilogram·Kelvin) (J/(kg·K))

The Joule/(Kilogram·Kelvin) is a unit of Specific Heat measurement (symbol: J/(kg·K)). 1 J/(kg·K) = 0.000238846 BTU/(lb·°F). Used in scientific and practical Specific Heat measurement applications.

BTU/(Pound·°F) (BTU/(lb·°F))

The BTU/(Pound·°F) is a unit of Specific Heat measurement (symbol: BTU/(lb·°F)). It is part of an internationally recognised measurement system used alongside the Joule/(Kilogram·Kelvin).

History & origin

Both the Joule/(Kilogram·Kelvin) and BTU/(Pound·°F) developed through the standardisation of Specific Heat measurement. Converting between them is a common requirement in science, engineering, and everyday applications where different measurement systems are used.

Common use: Joule/(Kilogram·Kelvin) to BTU/(Pound·°F) conversion is needed when working with international standards, scientific publications, or reference materials that use different unit systems for Specific Heat measurement.