Specific Heat Converter
J/kg·K · kJ/kg·K · BTU/lb·°F · cal/g·°C · kcal/kg·°C
Convert specific heat capacity units instantly between J/kg·K, kJ/kg·K, BTU/lb·°F, cal/g·°C, and kcal/kg·°C. Essential for chemical engineering, thermodynamics, HVAC design, and materials science.
Quick Reference
- 1 BTU/lb·°F = 4,186.8 J/kg·K
- 1 cal/g·°C = 4,186.8 J/kg·K
- Water = 4,186 J/kg·K
About Specific Heat Capacity
Specific heat capacity (c) is the energy required to raise 1 kg of a substance by 1 K. It describes how well a material stores thermal energy. The SI unit is J/kg·K. Water’s unusually high value of 4,186 J/kg·K makes it ideal for cooling and heating systems.
Unit Systems
The SI system uses J/kg·K or kJ/kg·K. The imperial/US system uses BTU/(lb·°F). The calorie-based system uses cal/g·°C or kcal/kg·°C. Since 1 cal = 4.1868 J, the numerical value of BTU/lb·°F and cal/g·°C are equal — both equal 4,186.8 J/kg·K.
Reference Values — Common Materials
Worked Examples
1 BTU/lb·°F to J/kg·K
1 × 4,186.8 = 4,186.8
4.186 kJ/kg·K to BTU/lb·°F
4,186 ÷ 4,186.8 = 0.99981
1 cal/g·°C to J/kg·K
(thermochemical calorie)
2.09 J/g·K to kJ/kg·K
2.09 J/g·K = 2.09 kJ/kg·K
When You Need This Converter
Chemical Engineering
Calculate heat duties for reactors and heat exchangers using Q = mcΔT with consistent units.
HVAC Design
Size heating and cooling systems using BTU/lb·°F values common in US engineering practice.
Materials Science
Compare thermal properties across metals, polymers, and composites in different unit systems.
Food Processing
Use cal/g·°C for pasteurization and refrigeration calculations in food science applications.
Thermal Management
Select coolants and heat storage materials for electronics and industrial processes.
Physics Education
Convert between SI and traditional units when working problems from different textbooks.
Mental Math Tips
BTU/lb·°F to J/kg·K
Multiply by ~4,187. Water’s 1 BTU/lb·°F = 4,186.8 J/kg·K is the key anchor value.
kJ/kg·K to J/kg·K
Simply multiply by 1,000. A value of 4.186 kJ/kg·K = 4,186 J/kg·K.
cal/g·°C equals J/g·K
Numerically, 1 cal/g·°C ≈ 4.187 J/g·K = 4,187 J/kg·K. The calorie and joule differ by this factor.